![]() ![]() ![]() The bug is "Verified" which means the MySQL team acknowledges it as a bug, but there is no fix and no estimate for when there will be a fix. This bug was reported in February 2021: (and also the duplicate bug ysth links to in the comments above). SystemError: invalid column constraint_name for resultset Then, click on the Add Foreign Key button. Next, click on the Foreign Keys tab at the bottom of the screen. First, open the table that you want to add the foreign key to in the Workbench. Create your relations (add foreign keys) Select the appropriate relationship type from the toolbar In the diagram, click on the header of the table you want. t_string(i, rset.stringFieldValueByName(field) or "" if format_func is None else format_func(rset.stringFieldValueByName(field))) Adding a foreign key to an existing MySQL table is a simple process that can be done via the MySQL Workbench. I checked the log (Help->Show Log File) and saw this: 10:15:53 : Error initializing tab constraints: Traceback (most recent call last):įile "/Applications/MySQLWorkbench.app/Contents/Resources/plugins/sqlide_tableman_ext.py", line 1183, in show_tableįile "/Applications/MySQLWorkbench.app/Contents/Resources/plugins/sqlide_tableman_ext.py", line 854, in show_tableįile "/Applications/MySQLWorkbench.app/Contents/Resources/plugins/sqlide_catalogman_ext.py", line 373, in refreshįile "/Applications/MySQLWorkbench.app/Contents/Resources/plugins/sqlide_catalogman_ext.py", line 367, in preload_data In other words, MySQL will not verify the consistency of. Unhandled exception: invalid column constraint_name for resultset To disable foreign key checks, you set the foreignkeychecks variable to zero as follows: To re-enable foreign key constraint check, you set the value of the foreignkeychecks to 1: Notice that setting foreignkeychecks to 1 does not trigger any validation of the existing table data. I pressed the "refresh" button and got this message: In MySQL, foreign key constraints are checked immediately, so NO ACTION is the same as. Some database systems have deferred checks, and NO ACTION is a deferred check. ![]() I viewed the foreign keys tab as you did. The MySQL Server rejects the delete or update operation for the parent table if there is a related foreign key value in the referenced table. I ran SHOW CREATE TABLE child and the output shows the foreign key.īut MySQL Workbench apparently has a bug showing the foreign key in the visual table information. NettetTo add a new column to MySQL, following is the syntax of the SQL Query: ALTER TABLE tablename ADD COLUMN newcolumnname AUTOINCREMENT PRIMARY KEY. It successfully created the child table with its foreign key. If Im understanding your question correctly, I believe you can do this from the Foreign Keys tab on the table itself. I tested your example tables in MySQL Workbench 8.0.28. ![]()
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